\Ans{$x^3-x-4=0$
	
	$f(1)=-4$
	
	$f(2)=2$
	
	so, the root lies between 1 and 2
	
	
	$$x_1=1/2(1+2)=1.5$$
	
	
	Step1: $x_1=1.5$, $f(x_1)=-2.125$
	
	Step2: $x_2=1.75$, $f(x_2)=-0.390625$
	
	Step3: $x_3=1.875$, $f(x_3)=0.7167$
	
	Step4: $x_4=1.8125$, $f(x_4)=0.141$
	
	Step5: $x_5=1.78125$, $f(x_5)=-0.129$
	
	Approximate value is 1.78125}